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pyspark-rdd-map.py
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pyspark-rdd-map.py
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# -*- coding: utf-8 -*-
"""
author SparkByExamples.com
"""
from pyspark.sql import SparkSession
spark = SparkSession.builder.appName('SparkByExamples.com').getOrCreate()
data = ["Project",
"Gutenberg’s",
"Alice’s",
"Adventures",
"in",
"Wonderland",
"Project",
"Gutenberg’s",
"Adventures",
"in",
"Wonderland",
"Project",
"Gutenberg’s"]
rdd=spark.sparkContext.parallelize(data)
rdd2=rdd.map(lambda x: (x,1))
for element in rdd2.collect():
print(element)
data = [('James','Smith','M',30),
('Anna','Rose','F',41),
('Robert','Williams','M',62),
]
columns = ["firstname","lastname","gender","salary"]
df = spark.createDataFrame(data=data, schema = columns)
df.show()
rdd2=df.rdd.map(lambda x:
(x[0]+","+x[1],x[2],x[3]*2)
)
df2=rdd2.toDF(["name","gender","new_salary"] )
df2.show()
#Referring Column Names
rdd2=df.rdd.map(lambda x:
(x["firstname"]+","+x["lastname"],x["gender"],x["salary"]*2)
)
#Referring Column Names
rdd2=df.rdd.map(lambda x:
(x.firstname+","+x.lastname,x.gender,x.salary*2)
)
def func1(x):
firstName=x.firstname
lastName=x.lastname
name=firstName+","+lastName
gender=x.gender.lower()
salary=x.salary*2
return (name,gender,salary)
rdd2=df.rdd.map(lambda x: func1(x)).toDF().show()
rdd2=df.rdd.map(func1).toDF().show()