-
Notifications
You must be signed in to change notification settings - Fork 0
/
FrogJump
43 lines (30 loc) · 1.37 KB
/
FrogJump
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
A small frog wants to get to the other side of the road. The frog is currently located at position X and wants to get to a position greater than or equal to Y. The small frog always jumps a fixed distance, D.
Count the minimal number of jumps that the small frog must perform to reach its target.
Write a function:
function solution($X, $Y, $D);
that, given three integers X, Y and D, returns the minimal number of jumps from position X to a position equal to or greater than Y.
For example, given:
X = 10
Y = 85
D = 30
the function should return 3, because the frog will be positioned as follows:
after the first jump, at position 10 + 30 = 40
after the second jump, at position 10 + 30 + 30 = 70
after the third jump, at position 10 + 30 + 30 + 30 = 100
Write an efficient algorithm for the following assumptions:
X, Y and D are integers within the range [1..1,000,000,000];
X ≤ Y.
**************************************** SOLUTION ************************************************
if ((!is_integer($X) || ($X < 1 || $X > 1000000000)) ||
(!is_integer($Y) || ($Y < 1 || $Y > 1000000000)) ||
(!is_integer($D) || ($D < 1 || $D > 1000000000)) ||
$X > $Y
) {
return 0;
}
$distance = $Y - $X;
$jumpsRequired = $distance / $D;
if (intdiv($distance, $D) !== 0) {
$jumpsRequired++;
}
return (int)$jumpsRequired;