-
Notifications
You must be signed in to change notification settings - Fork 13
/
1315-sum-of-nodes-with-even-valued-grandparent.py
53 lines (39 loc) · 1.7 KB
/
1315-sum-of-nodes-with-even-valued-grandparent.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
"""
Problem Link: https://leetcode.com/problems/sum-of-nodes-with-even-valued-grandparent/
Given a binary tree, return the sum of values of nodes with even-valued grandparent.
(A grandparent of a node is the parent of its parent, if it exists.)
If there are no nodes with an even-valued grandparent, return 0.
Example 1:
Input: root = [6,7,8,2,7,1,3,9,null,1,4,null,null,null,5]
Output: 18
Explanation: The red nodes are the nodes with even-value grandparent while the blue nodes are the even-value grandparents.
Constraints:
The number of nodes in the tree is between 1 and 10^4.
The value of nodes is between 1 and 100.
"""
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def sumEvenGrandparent(self, root: TreeNode) -> int:
def helper(root, parent=None, grand_parent=None):
if not root:
return 0
val = root.val if grand_parent and grand_parent.val % 2 == 0 else 0
return val + helper(root.left, root, parent) + helper(root.right, root, parent)
return helper(root)
class Solution1:
def sumEvenGrandparent(self, root: TreeNode) -> int:
self.sum = 0
def helper(root, parent=None, grand_parent=None):
if not root:
return 0
if grand_parent and grand_parent.val % 2 == 0:
self.sum += root.val
helper(root.left, root, parent)
helper(root.right, root, parent)
helper(root)
return self.sum