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wip 5.4
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marcbezem committed Nov 7, 2024
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58 changes: 42 additions & 16 deletions actions.tex
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Expand Up @@ -953,7 +953,7 @@ \section{Fixed points and orbits}
$G$, we'll mostly work in that generality.
\begin{definition}
\label{def:orbittype}
If $X : G\to\UU$, then the \emph{orbit type}\index{orbit type}
If $X : \BG\to\UU$, then the \emph{orbit type}\index{orbit type}
of the action is\footnote{%
The superscripts and subscripts are decorated with ``$hG$'',
following a convention in homotopy theory.
Expand Down Expand Up @@ -1071,14 +1071,14 @@ \section{Fixed points and orbits}
Surjectivity follows from the connectivity of $\BG$.
By~\cref{rem:set-trunc-as-quotient},
$X/G \jdeq \setTrunc{X_{hG}}$ is itself the
set quotient of $X_{hg} \jdeq \sum_{z:\BG}X(z)$ by
set quotient of $X_{hG} \jdeq \sum_{z:\BG}X(z)$ by
the relation $\sim$ defined by letting $(z,x)\sim(w,y)$
if and only if $\exists_{g:z\eqto w}(g\cdot x=y)$.
Thus,~\cref{thm:quotient-property} gives the
desired conclusion.
\end{proof}
Thus, both the underlying set $X(\shape_G)$ and the orbit type
$X_{hg}$ have equivalence relations with quotient set $X/G$.\footnote{%
$X_{hG}$ have equivalence relations with quotient set $X/G$.\footnote{%
This also justifies the notation $X/G$.
We have a diagram of surjective maps:
\[
Expand All @@ -1093,21 +1093,22 @@ \section{Fixed points and orbits}
If $X : \BG \to \Set$ is a $G$-set, and $x : X(\shape_G)$ is an
element of the underlying set, then we let
\begin{enumerate}
\item $G_x \defeq \Aut_{X_{hg}}(\shape_G,x)$
\item $G_x \defeq \Aut_{X_{hG}}(\shape_G,x)$
be the \emph{stabilizer group}\index{stabilizer}%
\index{group!stabilizer} at $x$, and
\item $G\cdot x \defeq \setof{y : X(\shape_G)}{[x] =_{X/G} [y]}$
be the \emph{orbit}\index{orbit} of $x$.\qedhere
\end{enumerate}
\end{definition}
Note that the classifying type $\BG_x$ of $G_x$
is identified with the fiber of $\settrunc{\blank} : X_{hg} \to X/G$,
is identified with the fiber of $\settrunc{\blank} : X_{hG} \to X/G$,
and $G\cdot x$ (pointed at $x$)
is identified with the fiber of $[\blank] : X(\shape_G) \to X/G$,
both taken at $[x]$, the orbit containing $x$.

Also, the base point of $\BG_x$ depends on the choice of $x$,
but the underlying type $(\BG_x)_\div$ only depends on $[x]:X/G$.
but the underlying type $(\BG_x)_\div$, \MB{being a connected component,}
only depends on $[x]:X/G$.
Thus, we can decompose our diagram by writing $X(\shape_G)$ and $X_{hG}$
as sums of the respective fibers.\footnote{%
Yielding the diagram
Expand All @@ -1118,14 +1119,16 @@ \section{Fixed points and orbits}
\& X/G, \&
\end{tikzcd}
\]
where we use $b$ to denote a \emph{bane}/orbit. (Too cute?)}
where we use $b$ to denote a \emph{bane}/orbit. (Too cute?
\MB{Unclear because of "orbit set". Orbit is pointed bane? Bane is unpointed
orbit? What about saying in 5.4.1 that $X/G$ is the set of (unpointed) orbits?})}

The stabilizer group $G_x$ comes equipped with a homomorphism
$i_x : \Hom(G_x,G)$, classified by
the projection $\fst:X_{hG} \to \BG$.\footnote{%
Since the projection is still a \covering, $\iota_x$ is a monomorphism
(\cref{lem:eq-mono-cover}), so $G_x$ together with $i_x$
becomes a \emph{subgroup} of $G$.}
(\cref{def:typeofmono}), so $G_x$ together with $i_x$
becomes a \emph{subgroup} of $G$.\MB{Promote to lemma?}}
There are two possible extreme cases that are important:
\begin{definition}\label{def:invariant-free}
Let $X$ be a $G$-set and $x:X(\shape_G)$ an element of the underlying set.
Expand All @@ -1140,29 +1143,31 @@ \section{Fixed points and orbits}
\end{definition}

\begin{lemma}\label{lem:invariant-char}
Given a $G$-set $X$, an element $x:(\shape_G)$ is
Given a $G$-set $X$, an element $x:X(\shape_G)$ is
invariant if and only if the orbit $G\cdot x$ is contractible,
\ie $x = g\cdot x$ for all $g:\USymG$.
\end{lemma}
\begin{proof}
The orbit $G\cdot x$ is the fiber of $\Bi_x : \BG_x \ptdto \BG$
at $\shape_G$. Since $\BG$ is connected,
this is contractible if and only if all fiber of $\Bi$ are contractible,
this is contractible if and only if all fibers of $\Bi$ are contractible,
\ie $\Bi_x$ is an equivalence, which in turn is equivalent to $i_x$
being an isomorphism.
\end{proof}

\begin{lemma}\label{lem:free-pt-char}
Given a $G$-set $X$, an element $x:(\shape_G)$ is\marginnote{%
Given a $G$-set $X$, an element $x:X(\shape_G)$ is\marginnote{%
Doesn't fit well here; move to where?}
free if and only if the (surjective) map
$\blank \cdot x : G \to G\cdot x$ is injective
$\blank \cdot x : \USymG \to G\cdot x$ is injective
(and hence a bijection).
\end{lemma}
\begin{proof}
Consider two elements of the orbit, say $g\cdot x,g'\cdot x$ for $g,g':\USymG$.
We have $g\cdot x=g' \cdot x$ if and only if $x = \inv{g} g'\cdot x$
if and only if $\inv{g} g'$ lies in $\USymG_x$.
\MB{Now apply \cref{xca:connected-trivia} yielding that that
$G_x$ is trivial iff $\USymG_x$ is contractible.}
\end{proof}

When $X : \BG \to \Set$ is a $G$-set for an ordinary group $G$,
Expand Down Expand Up @@ -1190,19 +1195,40 @@ \section{Fixed points and orbits}
\begin{proof}
Fix an invariant $x : X(\shape_G)$,
so $g\cdot x = x$ for all $g: \USymG$.
We need to show that the type
We need to show that the type\footnote{%
\MB{Isn't this the Yoneda lemma? Is the following argument OK?
Call the type $T_x$. It is a proposition since $\BG$ is connected
(for all $x$, useful to point out). So it suffices to construct an
element $f:T_x$. Since $x$ is invariant, $\Bi_x\jdeq\fst$ is an equivalence.
Hence all $\inv\Bi_x(z)$ are contractible, and they are equivalent with
$\sum_{y:X(z)}\Trunc{(z,y)\eqto(\sh_G,x)}$ (by contracting out, \cref{lem}).
This gives $f$, and we get the proposition $x=f(\sh_G)$ from
$\Trunc{(\sh_G,f(\sh_G))\eqto(\sh_G,x)}$, again by the invariance of $x$.
}}
\[
\sum_{f : \prod_{z:\BG}X(z)}f(\shape_G)=x
\sum_{f : \prod_{z:\BG}X(z)} x=f(\shape_G)
\]
is contractible.
This is equivalent to the type of pointed sections
This is equivalent to the type of pointed sections\footnote{%
\MB{See ft 52 on p. 40 which had to be corrected: a section is a pair.}}
of the projection $\fst : (X_{hG},x) \ptdto \BG$.
Since $\BG$ is connected, this is in turn equivalent
to the type of pointed sections of $\Bi_x : \BG_x \ptdto \BG$,
\ie the type of sections of the inclusion homomorphism $i_x:\Hom(G_x,G)$.
This is a proposition, and it's true if and only if $i_x$ is an isomorphism.
\end{proof}

\begin{xca}\label{xca:Gset-A->B}
\MB{New, w.i.p.}
Let $G$ be the group $\SG_2\times\SG_2$ and $X$ the $G$-set mapping
any pair $(A,B)$ of $2$-element sets to the set $A\to B$.
Elaborate the action of $G$ on $X(\sh_G)$ and determine the
set of orbits and the set of fixed points.
%Using that any fixed point $f$ of $X$ is completely determined by its
%value $f(\sh) : X(\sh_G)$, determine all fixed points.
\end{xca}


\section{The classifying type is the type of torsors}
\label{sec:torsors}
This section can be seen as a motivation for the use of torsors.
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2 changes: 1 addition & 1 deletion intro-uf.tex
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Expand Up @@ -2710,7 +2710,7 @@ \section{More on equivalences; surjections and injections}
in other words, we have a function of type
$\prod_{b:B} \sum_{a:A} (b \eqto f(a))$.
This is equivalent to saying we have a function
$g:B\to A$ such that $f\circ g \eqto \id_B$
$g:B\to A$ and an identification $p: f\circ g \eqto \id_B$
(such a $g$ is called a \emph{section} of $f$).}
\end{definition}

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