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Simple app to generate DFA from NFA and check if the string applies to a rule

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Simple app to convert NFA to DFA and check if the string applies to a rule.

Breif definition about DFA and NFA.


DFA: A DFA is a finite state machine that accepts or rejects strings of symbols and only produce a uniques computation (or run) of the automation for each input string. Deterministic refers to the uniqueness of the computation. In search of the simplest models to capture finite-state machines.
DFA

A DFA can be represented by a 5-tuple (Q, ∑, δ, q0, F) where −

  1. Q is a finite set of states.

  2. ∑ is a finite set of symbols called the alphabet.

  3. δ is the transition function where δ: Q × ∑ → Q

  4. q0 is the initial state from where any input is processed (q0 ∈ Q).

  5. F is a set of final state/states of Q (F ⊆ Q).

Learn more about DFA here.

NFA: n NFA, similar to a DFA, consumes a string of input symbols. For each input symbol, it transitions to a new state until all input symbols have been consumed. Unlike a DFA, it is non-deterministic, i.e., for some state and input symbol, the next state may be nothing or one or two or more possible states.
NFA

An NDFA can be represented by a 5-tuple (Q, ∑, δ, q0, F) where −

  1. Q is a finite set of states.

  2. ∑ is a finite set of symbols called the alphabets.

  3. δ is the transition function where δ: Q × ∑ → 2Q

    (Here the power set of Q (2Q) has been taken because in case of NDFA, from a state, transition can occur to any combination of Q states)

  4. q0 is the initial state from where any input is processed (q0 ∈ Q).

  5. F is a set of final state/states of Q (F ⊆ Q).

Learn more about NFA here.

Conversion of NFA to DFA:


Every DFA is an NFA, but not vice-versa. There is an equivalent DFA for every NFA.

The transition funtion δ is the only difference, otherwise everything else remains the same between a DFA and an NFA.

For example:

Let L be a set of all strings over (0,1) that starts with '0'.

L = { Set of all strings over (0,1) that starts with '0' }

Therefore, ∑ = {0,1}

NFA:
NFA

DFA

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Simple app to generate DFA from NFA and check if the string applies to a rule

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